. Let 
. Then 
. In modulo 
, the last equality yields
(mod ). Therefore, c2 divides 4b and
. Now 
( !). Finally, 
which gives 
. Thus 
and we get a = 0, no solution.Solution :
Case 1: b = 1. Then the only solution is (3,1).
Case
2: . Let . Then . In modulo , the last equality yields
(mod ). Therefore, c2 divides 4b and
. Now ( !). Finally, which gives . Thus and we get a = 0, no solution.
The only solution is (3,1).